In this post, I will share some important questions which are frequently asked in competitive examinations such as SSC, UPSC and state PSCs.
-
Which of the following is used when the work is of national importance?
- Plane surveying
- Geodetic surveying
- Cadastral surveying
- none of the above
View AnswerAnswer: b
In geodetic surveying, the curvature of the Earth is taken into account due to which accuracy of work increases. -
Plane surveying is used when the area to be surveyed is less than ______ sq km.
- 155
- 195
- 225
- 250
View AnswerAnswer: d
-
When natural features of a country is to be surveyed then which of the following surveys is done?
- Topographical Survey
- Cadastral Survey
- City Survey
- Marine Survey
View AnswerAnswer: a -
Which of the following surveys is used to fix the boundaries of municipalities?
- Topographical Survey
- Cadastral Survey
- City Survey
- Marine Survey
View AnswerAnswer: b
Cadastral surveys are used to fix property lines, the calculation of land area and to fix land boundaries of municipalities and of state and federal jurisdictions. -
Which of the following surveys is used to determine the absolute location of any point?
- Topographical Surveys
- Cadastral Surveys
- Astronomical Surveys
- Astrological Surveys
View AnswerAnswer: c -
Which of the following surveys needs the least work on the field?
- Chain Survey
- Plane Table Survey
- Traverse Survey
- Triangulation Survey
View AnswerAnswer: a -
Consider the following statements and choose the correct answer.
- The relative positions of the points to be surveyed should be located by measurement from at least two points of reference, the positions of which may not be fixed in advance.
- The work of surveying should be done from whole to part.
- Only (i) is correct
- Both (i) and (ii) are correct
- (i) is wrong and (ii) is correct
- (i) is correct and (ii) is wrong
View AnswerAnswer: c
The above two statements are principles of surveying:
The relative positions of the points to be surveyed should be located by measurement from at least two points of reference, the positions of which have already been fixed.
The work of surveying should be done from whole to part. -
The principle of surveying "whole to part" is used to ...
- prevent the accumulation of errors
- localise minor errors
- Both (a) and (b)
- None of the above
View AnswerAnswer: c -
Which of the following is the largest scale?
- 1 cm = 10 m
- 1/500
- 10 cm = 10 m
- 1/1000
View AnswerAnswer: c
(a)1 cm = 10 cm ⇒ RF = 1/1000
(b)1/500
(c)10 cm = 10 m ⇒ 10 cm = 1000 cm ⇒ RF = 1/100
(d)1/1000
Therefore, the largest scale is 10 cm = 10 m -
Select the correct statement.
- If the RF is less, the map would be detailed but difficult to create
- If the RF is more, the map would be detailed but difficult to create
- If the RF is more, the map would not be detailed and easy to create
- none of the above
View AnswerAnswer: b
When the RF is more, the scale will be large and hence more details can be shown on the maps which will increase the work. -
How many plain scales IS: 1491:1959 has recommended?
- 4
- 5
- 6
- 7
-
Select the correct statement.
- (n+1) divisions of the main scale = n divisions of the direct vernier
- n divisions of the main scale = (n-1) divisions of the retrograde vernier
- (n+1) divisions of the main scale = n divisions of the retrograde vernier
- n divisions of the main scale = (n-1) divisions of the direct vernier
View AnswerAnswer: c
In Direct Vernier, (n-1) divisions of the main scale = n divisions of the vernier
In Retrograde Vernier, (n+1) divisions of the main scale = n divisions of the vernier -
In an Extended Vernier ...
- (n-2) divisions of the main scale = n divisions of the vernier
- (n+2) divisions of the main scale = n divisions of the vernier
- (2n+2) divisions of the main scale = n divisions of the vernier
- (2n-2) divisions of the main scale = n divisions of the vernier
View AnswerAnswer: d -
A limb of an instrument is divided into 15 minutes. What will be the suitable number of divisions in vernier to read to 20 seconds?
- 35
- 65
- 40
- 45
View AnswerAnswer: d
$\text{Least Count}=\frac{s}{n}$
$\text{Least Count} = 20"$ ; $s=15'$
$20"=\frac{15\times 60}{n}$
$n=45$ -
A surveyor measured the distance between two points on the plan drawn to a scale of 1 cm = 20 m and the result was 936 m. Later, however, he discovered that he used a scale of 1 cm = 40 m. What is the true distance between the points?
- 468 m
- 468 cm
- 936 cm
- 468 km
View AnswerAnswer: a
RF of correct scale $=1/2000$
RF of the wrong scale $=1/4000$
As the RF of the wrong scale is half of that of correct scale, the true length will be half of the measured length i.e., 468 m
$\text{Correct Length}=\frac{\text{RF of wrong scale}}{\text{RF of correct scale}}\times \text{measured Length}$
$\text{Correct Length}=\frac{1/4000}{1/2000}\times936 = 468 m$
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